题目如下：

On an infinite plane, a robot initially stands at (0, 0) and faces north.  The robot can receive one of three instructions:

• "G": go straight 1 unit;
• "L": turn 90 degrees to the left;
• "R": turn 90 degress to the right.

The robot performs the instructions given in order, and repeats them forever.

Return true if and only if there exists a circle in the plane such that the robot never leaves the circle.

 

Example 1:

Input: "GGLLGG"Output: trueExplanation: The robot moves from (0,0) to (0,2), turns 180 degrees, and then returns to (0,0).When repeating these instructions, the robot remains in the circle of radius 2 centered at the origin.

Example 2:

Input: "GG"Output: falseExplanation: The robot moves north indefinetely.

Example 3:

Input: "GL"Output: trueExplanation: The robot moves from (0, 0) -> (0, 1) -> (-1, 1) -> (-1, 0) -> (0, 0) -> ...

 

Note:

1. 1 <= instructions.length <= 100
2. instructions[i] is in {'G', 'L', 'R'}

解题思路：看到这个题目，我的感觉就是如果能回到起点，应该是执行instructions一次，两次或者四次。嘿嘿，当然我也不知道怎么证明，反正能AC。

代码如下：

class Solution(object):    def process(self,start,instructions):        for i in instructions:            if i == 'G':                if start[2] == 'N':start[1] += 1                elif start[2] == 'S':start[1] -= 1                elif start[2] == 'E':start[0] += 1                elif start[2] == 'W':start[0] -= 1            elif i == 'L':                if start[2] == 'N':start[2] = 'W'                elif start[2] == 'S':start[2] = 'E'                elif start[2] == 'E':start[2] = 'N'                elif start[2] == 'W':start[2] = 'S'            elif i == 'R':                if start[2] == 'N':start[2] = 'E'                elif start[2] == 'S':start[2] = 'W'                elif start[2] == 'E':start[2] = 'S'                elif start[2] == 'W':start[2] = 'N'        return start    def isRobotBounded(self, instructions):        """        :type instructions: str        :rtype: bool        """        start = [0,0,'N']        end = self.process(start,instructions)        if end[0] == end[1] == 0:            return True        end = self.process(start, instructions)        if end[0] == end[1] == 0:            return True        end = self.process(start, instructions)        end = self.process(start, instructions)        if end[0] == end[1] == 0:            return True        return False